Here you can find the meaning of A projectile is projected with 3 ICAP 4 j cap 5 I camp m per second projection is taken as origin and East north and vertically upward direction and taken as positive x y z directions respectively is equal to 10 metre per second -2 for in SI units location of particle when it is at its maximum height is? defined & explained in the simplest way possible. Information about A projectile is projected with 3 ICAP 4 j cap 5 I camp m per second projection is taken as origin and East north and vertically upward direction and taken as positive x y z directions respectively is equal to 10 metre per second -2 for in SI units location of particle when it is at its maximum height is? covers all topics & solutions for JEE 2023 Exam.įind important definitions, questions, meanings, examples, exercises and tests below for A projectile is projected with 3 ICAP 4 j cap 5 I camp m per second projection is taken as origin and East north and vertically upward direction and taken as positive x y z directions respectively is equal to 10 metre per second -2 for in SI units location of particle when it is at its maximum height is?. The Question and answers have been prepared The location of the particle when it is at its maximum height is 3i + 4j + 5.5k m.Ī projectile is projected with 3 ICAP 4 j cap 5 I camp m per second projection is taken as origin and East north and vertically upward direction and taken as positive x y z directions respectively is equal to 10 metre per second -2 for in SI units location of particle when it is at its maximum height is? for JEE 2023 is part of JEE preparation. Therefore, the location of the projectile at the maximum height is:
The horizontal component of the displacement is zero, as the projectile does not move horizontally at the maximum height As the projectile is at its maximum height, the vertical component of the displacement is equal to the maximum height reached by the projectile, i.e., 5.5 m The location of the projectile at the maximum height can be calculated using the formula: Therefore, the time taken to reach maximum height is equal to the time taken for the projectile to reach the maximum height and come back to the ground At the maximum height, the velocity of the projectile becomes zero Step 4: Location of Particle at Maximum Height The time taken by the projectile to reach the maximum height can be calculated using the formula: Step 3: Time Taken to Reach Maximum Height
As the angle of projection is not given, we can assume that the projectile is projected at an angle of 45° Where H = maximum height, u = initial velocity, θ = angle of projection, g = acceleration due to gravity The maximum height reached by the projectile can be calculated using the formula: Step 2: Maximum Height Reached by Projectile The initial velocity of the projectile is given as 3i + 4j + 5k m/s Location of particle when it is at its maximum height Projection is taken as origin and East north and vertically upward direction and taken as positive x y z directions respectively Projectile is projected with 3i + 4j + 5k m/s
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